QuantumATK Forum
QuantumATK => General Questions and Answers => Topic started by: Om Prakash Upadhyay on February 7, 2017, 15:44
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Does the electron temperature given in ATK-VNL refers the normal surrounding temperature or any other else?
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The electron temperature in the ATK reflects a degree of broadening of the Fermi-Dirac distribution (or its derivative), which is otherwise a discontinuous step function (or Delta function for the derivative) at T=0 K that is hard to handle in the numerical calculations such as that done with the ATK.
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If we increase the electron temperature then can we say that it is temperature dependent calculations?
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If the smearing (temperature) values adopted in the DFT calculations significantly affect your results, it means that you have to decrease the artificial temperature value. It also means that you should first decide on what is the target accuracy for the physical quantities you want to calculate. This is rather similar to choosing any other computational settings for numerical calculations, in general, e.g., choosing mesh density, k-point sampling and so on.
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So, to be clear, the answer is no, a higher electron temperature in DFT is just a numerical trick to ensure the convergence is smoother. Formally, DFT is a T=0 theory unless you add extra effects like electron-phonon scattering, which is possible in ATK (see tutorials).
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Thanks alot for reply.
But actually what I found that, when I increase the electron temperature in Cu2O nanowie, it is observed that the nanowire which shows hal fmetallic nature at 300K , shows matallic nature above 2000K (depending on diameter) rather half metallic. What is the main reason behind it???
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You are probably broadening the electronic occupations around the Fermi level too much, such that states above the T=0 K Fermi level becomes occupied.
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Thanks alot for reply.
But actually what I found that, when I increase the electron temperature in Cu2O nanowie, it is observed that the nanowire which shows hal fmetallic nature at 300K , shows matallic nature above 2000K (depending on diameter) rather half metallic. What is the main reason behind it???
Please refer to the literature survey for the different types of computational methods on Cu2O
www.iaea.org/inis/collection/NCLCollectionStore/_Public/43/041/43041487.pdf