QuantumATK Forum

QuantumATK => General Questions and Answers => Topic started by: ams_nanolab on February 10, 2017, 21:13

Title: T(E) or Ge(E)
Post by: ams_nanolab on February 10, 2017, 21:13

In the manual

http://docs.quantumwise.com/manuals/Types/TransmissionSpectrum/TransmissionSpectrum.html
mentions A fully transmitting channel contributes 1 per spin. If you sum the spin channels, the total transmission of an ideal system is 2. Often, it is the energy dependent conductance which is reported in articles

Ge(E)=(e^2/h)T(E)

If total transmission of an ideal system is 2, what does quantumwise actually plot for the transmission spectra T(e) or Ge(E) ?

Because in many cases the value of transmission is well in excess of 2.

Title: Re: T(E) or Ge(E)
Post by: Anders Blom on February 10, 2017, 23:50

Asked and answered many times. There can be many channels at any energy, for instance px and py.

Title: Re: T(E) or Ge(E)
Post by: Anders Blom on February 10, 2017, 23:54

See e.g. http://quantumwise.com/forum/index.php?topic=282.msg1618#msg1618

Title: Re: T(E) or Ge(E)
Post by: ams_nanolab on February 11, 2017, 10:20

Okay, my bad. So it is indeed the T(E).