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QuantumATK => Scripts, Tutorials and Applications => Topic started by: gozde on August 12, 2022, 15:55

Title: Zn-ZnO-Zn Transport Calculation
Post by: gozde on August 12, 2022, 15:55
Hello,

I have a question about Zn-ZnO-Zn junction tutorial. I tried to create the geometry by following this link "https://forum.quantumatk.com/index.php?topic=5320.msg22991#msg22991", however I can not understand how we select the smallest possible number of atoms, repeat a bit on both sides of the interface.

Also should we make any transformation when retrieving the Zn and ZnO geometries since the first one is hexagonal and the latter is face centered cubic?

Thanks.
Title: Re: Zn-ZnO-Zn Transport Calculation
Post by: gozde on September 25, 2022, 11:37
Can any one guide me about this issue?
Title: Re: Zn-ZnO-Zn Transport Calculation
Post by: apnichol on January 27, 2023, 05:12
It's probably too long a period of time since there was any response to your post, but I thought I would give it a try. According to the previous forum post you are referencing, the selection of the "smallest atoms possible" is referring to the interface builder window with all calculated in-plane strains depending on whether the first layer, second layer, or both layers are strained. You want to select the dot on the lower panel that gives the lowest number of atoms while still minimizing the amount of in-plane strain resulting between the first and second layers.

The "repeat a bit on both sides of the interface" part would mean to add additional atomic layers to both sides of the interface using the "+" buttons you see under each displayed bulk material within the interface builder pulldown menu. Additional layers for each bulk material that are joined together to form the interface will be included in the supercell slab model. There are other ways to add more layers to both sides of the interface, but I will leave that out of the discussion for now. I hope that helps some.
Title: Re: Zn-ZnO-Zn Transport Calculation
Post by: gozde on February 1, 2023, 16:18
Thank you for your comments. I will go back to tutorial and make the calculations again under the guidance of your advice.