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« on: March 2, 2009, 12:17 »
Thank you, Anders Blom! I have told the answer to my pro, but he didn't agree with you.Can you give me sufficient reasons to help me to make my pro agree with you?
If the frimi level=0, then what is the real mean of the fermi energy in the exported transmission spectrum is? As can we see from the exported transmission spectrum , for Electrodes Calculation
#
----------------------------------------------------------------
# sc 0 : Fermi Energy = 0.00000 Ry
#-------------------------------------------------------------------------------
# Mulliken Population for sc 0
#-------------------------------------------------------------------------------
0 Li q = 1.00000 [ s: 1.000, py: 0.000, pz: 0.000, px: 0.000 ]
1 Li q = 1.00000 [ s: 1.000, py: 0.000, pz: 0.000, px: 0.000 ]
2 Li q = 1.00000 [ s: 1.000, py: 0.000, pz: 0.000, px: 0.000 ]
3 Li q = 1.00000 [ s: 1.000, py: 0.000, pz: 0.000, px: 0.000 ]
#-------------------------------------------------------------------------------
# Total Charge = 4.00000
#-------------------------------------------------------------------------------
# sc 1 : Fermi Energy = -0.41765 Ry dRho = 4.6383E+000
#-------------------------------------------------------------------------------
# Mulliken Population for sc 1
#-------------------------------------------------------------------------------
0 Li q = 0.99999 [ s: 0.476, py: 0.186, pz: 0.153, px: 0.186 ]
1 Li q = 1.00001 [ s: 0.476, py: 0.186, pz: 0.153, px: 0.186 ]
2 Li q = 1.00000 [ s: 0.476, py: 0.186, pz: 0.153, px: 0.186 ]
3 Li q = 1.00001 [ s: 0.476, py: 0.186, pz: 0.153, px: 0.186 ]
#-------------------------------------------------------------------------------
# Total Charge = 4.00000
#-------------------------------------------------------------------------------
# sc 2 : Fermi Energy = -0.41572 Ry dRho = 3.4473E-003
#-------------------------------------------------------------------------------
# Mulliken Population for sc 2
#-------------------------------------------------------------------------------
0 Li q = 0.99999 [ s: 0.476, py: 0.186, pz: 0.153, px: 0.186 ]
1 Li q = 1.00001 [ s: 0.476, py: 0.186, pz: 0.153, px: 0.186 ]
2 Li q = 1.00000 [ s: 0.476, py: 0.186, pz: 0.153, px: 0.186 ]
3 Li q = 1.00001 [ s: 0.476, py: 0.186, pz: 0.153, px: 0.186 ]
#-------------------------------------------------------------------------------
# Total Charge = 4.00000
#-------------------------------------------------------------------------------
# sc 3 : Fermi Energy = -0.39825 Ry Etot = -3.70151 Ry dRho = 3.4600E-002
#-------------------------------------------------------------------------------
# Mulliken Population for sc 3
#-------------------------------------------------------------------------------
0 Li q = 0.99999 [ s: 0.480, py: 0.185, pz: 0.150, px: 0.185 ]
1 Li q = 1.00001 [ s: 0.480, py: 0.185, pz: 0.150, px: 0.185 ]
2 Li q = 1.00000 [ s: 0.480, py: 0.185, pz: 0.150, px: 0.185 ]
3 Li q = 1.00001 [ s: 0.480, py: 0.185, pz: 0.150, px: 0.185 ]
#-------------------------------------------------------------------------------
# Total Charge = 4.00000
#-------------------------------------------------------------------------------
# sc 4 : Fermi Energy = -0.39824 Ry Etot = -3.70151 Ry dRho = 2.3260E-005 dEtot = 1.3067E-008 Ry
#-------------------------------------------------------------------------------
# Mulliken Population for sc 4
#-------------------------------------------------------------------------------
0 Li q = 0.99999 [ s: 0.480, py: 0.185, pz: 0.150, px: 0.185 ]
1 Li q = 1.00001 [ s: 0.480, py: 0.185, pz: 0.150, px: 0.185 ]
2 Li q = 1.00000 [ s: 0.480, py: 0.185, pz: 0.150, px: 0.185 ]
3 Li q = 1.00001 [ s: 0.480, py: 0.185, pz: 0.150, px: 0.185 ]
#-------------------------------------------------------------------------------
# Total Charge = 4.00000
#-------------------------------------------------------------------------------
AND AS FOR Equivalent Bulk Calculation (Initial Density for TwoProbe)
sc 23 : Fermi Energy = -0.35530 Ry Etot = -7301.92848 Ry dRho = 3.8679E-004 dEtot = -6.0960E-006 Ry
can you explain the feimi energy for me ?
thanks!!