The calculated system is C59W. The pseudoptentials for C and W you used are generated for the normal valence electron configurations, i.e., C: 2s^2 2p^2 ( 4 electrons); W: 6s^2 5d^4 (6 electrons). So the total number of valence electrons is 59*4 + 6 = 242. We expect the 121th molecular level (i.e., index of 120 in your attached picture) is the highest occupied one. From your results, this level seems to be degenerated with the 122th molecular level ((i.e., index of 121 in your attached picture). In such situation, which is contrast to what I said in my last reply, the use of "0.1 k" for electron temperature is not suitable. It would lead to a problem in determining the position of the highest occupied level. This is what you have met in your calculations.
Solution:
1) If you keep the use of non-spin polarization calculation (number_of_spins=1), you have to increase the value of electron temperature.
2) If you use the spin-polarization calculation(i.e., number_of_spins= 2), you can use small value of electron temperature as you already used.
The 2nd way is recommended because the spin-polarization calculation would give more reliable results.