Author Topic: Questions about the total energy of a twoprobe system!  (Read 4183 times)

0 Members and 1 Guest are viewing this topic.

Offline hhspace

  • Regular QuantumATK user
  • **
  • Posts: 19
  • Reputation: 0
    • View Profile
Questions about the total energy of a twoprobe system!
« on: January 17, 2011, 16:03 »
Hello, evergyone
    For ATK-Version 2008.10 (DFT edition), the manual shows that the total energy of a twoprobe system can be calculated and it mainly include three parts: Electron kinetic energy, Electrostatic energy, and Exchange-corr. energy. However, for ATK 10.8 (DFT edition) I find that for a twoprobe system or device configuration the total energy of it is divided into four parts: Electron kinetic energy, Exchange-corr. energy, Hartree energy, and Interaction energy with the pseudo potential ions and other electro-static external potentials.
    I want to know whether Electrostatic energy of ATK-Version 2008.10 equals to the sum of Hartree energy and Interaction energy of ATK 10.8? Is that true even when bias voltage is applied?
« Last Edit: February 4, 2011, 09:28 by hhspace »

Offline hhspace

  • Regular QuantumATK user
  • **
  • Posts: 19
  • Reputation: 0
    • View Profile
Re: Questions about the total energy of a twoprobe system!
« Reply #1 on: February 4, 2011, 11:01 »
Yes, you are correct. Do note however that ATK 10.8 doesn't actually compute the total energy for devices (although the function name would indicate so); it returns the free energy. There is a correction term which plays a role in particular at finite bias. The total energy is not a well-defined quantity unless there is charge conservation, which is not the case for open systems (device configurations).

Anders
« Last Edit: February 4, 2011, 11:30 by Anders Blom »