Now, by setting the right boundary condition to DirichletBoundaryCondition(vacuum + shift), the following Hartree differential potential can be obtained. Here, the vacuum is the projection of the average Hartree differential potential (about 4.4 eV) along the c-axis, and the shift is ±10 eV. the voltages of left and right electrode were set to 0 V.
My question is, is the strength of the electric field set by the shift here? If so, does the shift = 10 eV meaning that a 10 V electric field is applied to the surface? What is the relationship between the electrode voltage and the electric field?