Author Topic: about calculating strain at the interface  (Read 2042 times)

0 Members and 1 Guest are viewing this topic.

Offline debjani

  • New QuantumATK user
  • *
  • Posts: 3
  • Country: in
  • Reputation: 0
    • View Profile
about calculating strain at the interface
« on: September 1, 2017, 09:38 »
While constructing an interface, how are the strains calculated in ATK? The standard method of (difference in lattice parameter/respective lattice parameter) does not result into the same value as the displayed strain during interface construction. For example, if I am constructing an interface of MoS2 4X4X1 with Au[111] 4X4X1, strain on Au, as calculated from lattice mismatch is (3.16-2.88)/2.88 ~ 9.7%. However, while constructing this interface, ATK shows a strain of 0.83%. Please explain.

Offline Petr Khomyakov

  • QuantumATK Staff
  • Supreme QuantumATK Wizard
  • *****
  • Posts: 1290
  • Country: dk
  • Reputation: 25
    • View Profile
Re: about calculating strain at the interface
« Reply #1 on: September 1, 2017, 10:27 »
You can choose to strain MoS2 or Au surface structures, or both equally.

Regarding 0.84% vs 9.7 % of strain, as far as I can see the problem is that you have selected a larger supercell (which is not the one corresponding to the original 4x4 in-plane unit cell) in the Interface Builder, as there are many possible ways of building the MoS2(0001)|Au(111) interface structure.  When choosing the 4x4 cell, I get strain of 9.35 %, in good agreement with your estimate. I have also found a structure with strain of 0.84%, but it does not correspond to the originally-built 4x4 cell.

Offline debjani

  • New QuantumATK user
  • *
  • Posts: 3
  • Country: in
  • Reputation: 0
    • View Profile
Re: about calculating strain at the interface
« Reply #2 on: September 11, 2017, 08:53 »
Thank you so much for your reply! I could regain the strain ~8% after cleaving the Au[111] surface and choosing the right unit cell.