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General Questions and Answers / Re: Error Problem in loading Density of States (DOS) 2D plot
« on: October 28, 2016, 21:00 »
I am having the same problem in 2016.2 version, do I need to change something manually?
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The calculated system is C59W. The pseudoptentials for C and W you used are generated for the normal valence electron configurations, i.e., C: 2s^2 2p^2 ( 4 electrons); W: 6s^2 5d^4 (6 electrons). So the total number of valence electrons is 59*4 + 6 = 242. We expect the 121th molecular level (i.e., index of 120 in your attached picture) is the highest occupied one. From your results, this level seems to be degenerated with the 122th molecular level ((i.e., index of 121 in your attached picture). In such situation, which is contrast to what I said in my last reply, the use of "0.1 k" for electron temperature is not suitable. It would lead to a problem in determining the position of the highest occupied level. This is what you have met in your calculations.
Solution:
1) If you keep the use of non-spin polarization calculation (number_of_spins=1), you have to increase the value of electron temperature.
2) If you use the spin-polarization calculation(i.e., number_of_spins= 2), you can use small value of electron temperature as you already used.
The 2nd way is recommended because the spin-polarization calculation would give more reliable results.
If your molecule has HOMO-LUMO gap, you can use much smaller value for "electron_temperature", i.e., which tends to be fixed electron occupation.
What sort of analysis does this output come from? Does not look like a MolecularEnergySpectrum for a molecular configuration....
Occupancy = 2.0 means 2 electrons in that state, a spin-up and a spin-down electron (full occupancy). Without spin-polarization, anything less than 2 means partial or no occupancy.
But I do not understand how you can have partial occupancy in a molecular system. Would expect either 2 or 0, like in the MolecularEnergySpectrum below.Code+------------------------------------------------------------------------------+
| Molecular Energy Spectrum Report |
---------------------------------------------------------------------------- |
| Fermi level = -4.550063e+00 |
| Number of electrons = 52.000000 |
| Unit = eV |
| Eigenenergies given relative to the Fermi Level |
+------------------------------------------------------------------------------+
22 -4.396009e+00 2.000000e+00
23 -4.265472e+00 2.000000e+00
24 -2.548539e+00 2.000000e+00
25 -2.350585e+00 2.000000e+00
26 2.350626e+00 6.490006e-40
27 2.521805e+00 8.641132e-43
28 6.023727e+00 7.440152e-44
29 6.490207e+00 7.440152e-44
30 7.177419e+00 7.440152e-44
31 7.301969e+00 7.440152e-44
This question is about section 2 in the tutorial "Benzene Single-Electron Transistor" http://quantumwise.com/documents/tutorials/latest/BenzeneSET/index.html/index.htmlThank you very much!
In order to get the same numbers as shown in the tutorial, you need to set the Poisson Solver to Multigrid and the boundary conditions to Multipole. I realized yesterday that this is not shown explicitly in the tutorial, and we will add it when it is next updated.