« previous next »
Pages: [1]   Go Down

Author Topic: T(E) or Ge(E)  (Read 3173 times)

0 Members and 1 Guest are viewing this topic.

Offline ams_nanolab

  • Supreme QuantumATK Wizard
  • *****
  • Posts: 389
  • Country: in
  • Reputation: 11
    • View Profile
T(E) or Ge(E)
« on: February 10, 2017, 21:13 »
In the manual

http://docs.quantumwise.com/manuals/Types/TransmissionSpectrum/TransmissionSpectrum.html
mentions A fully transmitting channel contributes 1 per spin. If you sum the spin channels, the total transmission of an ideal system is 2. Often, it is the energy dependent conductance which is reported in articles

Ge(E)=(e^2/h)T(E)

If total transmission of an ideal system is 2, what does quantumwise actually plot for the transmission spectra T(e) or Ge(E) ?

Because in many cases the value of transmission is well in excess of 2.
Logged

Offline Anders Blom

  • QuantumATK Staff
  • Supreme QuantumATK Wizard
  • *****
  • Posts: 5576
  • Country: dk
  • Reputation: 96
    • View Profile
    • QuantumATK at Synopsys
Re: T(E) or Ge(E)
« Reply #1 on: February 10, 2017, 23:50 »
Asked and answered many times. There can be many channels at any energy, for instance px and py.
Logged

Offline Anders Blom

  • QuantumATK Staff
  • Supreme QuantumATK Wizard
  • *****
  • Posts: 5576
  • Country: dk
  • Reputation: 96
    • View Profile
    • QuantumATK at Synopsys
Re: T(E) or Ge(E)
« Reply #2 on: February 10, 2017, 23:54 »
Logged

Offline ams_nanolab

  • Supreme QuantumATK Wizard
  • *****
  • Posts: 389
  • Country: in
  • Reputation: 11
    • View Profile
Re: T(E) or Ge(E)
« Reply #3 on: February 11, 2017, 10:20 »
Okay, my bad. So it is indeed the T(E).
Logged
Pages: [1]   Go Up
« previous next »