Author Topic: About the unit of external potential  (Read 6385 times)

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Offline BlackBarrel

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About the unit of external potential
« on: December 24, 2012, 08:57 »
Dear Quantumwise Staff:
    Recently I calculate the external potential and get confused by its unit. Why is it in the unit of eV? Shouldn't it be V?
   
    PS: The manual says "ExternalPotential, returns the electrostatic potential due to the electrodes and gates in the system". How to tell the external potential from the internal one? Is the screening effect included in the external potential calculation?

    Thank you!

Offline zh

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Re: About the unit of external potential
« Reply #1 on: December 24, 2012, 12:39 »
The unit of a potential  should be eV rather that V.

Please read the background of ATK-DFT to understand the concept of external potential:
http://quantumwise.com/documents/manuals/latest/ReferenceManual/index.html/chap.atkdft.html#sect2.atkdft.kohn_sham_hamiltonian_solving.


Offline BlackBarrel

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Re: About the unit of external potential
« Reply #2 on: December 24, 2012, 15:05 »
So it is potential energy rather than electric potential? Then is there any way to get the electric potential in voltage induced by the gates? Actually I just want to view the electric field created by gates in my device. May I just divide the external potential (or maybe the difference between the potential of Vg=0 and that of infinite Vg ?) by the electron density?

Offline zh

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Re: About the unit of external potential
« Reply #3 on: December 25, 2012, 00:44 »
You may follow the concept of voltage drop to extract what you want:
http://quantumwise.com/publications/tutorials/mini-tutorials/98-i-v-curve-and-voltage-drop

Offline BlackBarrel

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Re: About the unit of external potential
« Reply #4 on: December 25, 2012, 06:05 »
Thank you very much, but the "voltage drop" is still in unit of eV (so why is it called voltage drop?). How could I get the electric field in the device?

BTW, I didn't know the object ElectrostaticDifferencePotential could directly be subtracted from each other. Do all properties' objects support arithmetic operators?

Offline zh

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Re: About the unit of external potential
« Reply #5 on: December 25, 2012, 12:41 »
Voltage drop (in unit of eV) =  |e| * Voltage drop (in unit of volt).  The electric field induced by the applied bias is calculated by the gradient of voltage drop in the unit of volt: E = -dV/dx.

"Do all properties' objects support arithmetic operators? "
Yes.

Offline Nordland

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Re: About the unit of external potential
« Reply #6 on: December 25, 2012, 18:29 »
"Do all properties' objects support arithmetic operators? "
Yes.
Yes to all real space properties.

Offline BlackBarrel

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Re: About the unit of external potential
« Reply #7 on: December 26, 2012, 06:17 »
Voltage drop (in unit of eV) =  |e| * Voltage drop (in unit of volt).  The electric field induced by the applied bias is calculated by the gradient of voltage drop in the unit of volt: E = -dV/dx.

"Do all properties' objects support arithmetic operators? "
Yes.

Many thanks to both of you. So it seems that one can easily divide any potential (external potential, electrostatic difference potential and effective potential) in eV by |e| to get potential in V, regardless of the electron density of the device. Is |e|=1.6E-19 here or |e|=1? Actually what I want to know is the electric field induced by the gates, so is it OK to subtract the external potential of Vg=0 from that of finite Vg?

BTW, what does it mean by real space properties? Is "Transmission Pathways" included? How can I calculate the net current flows into an atom, when there are arrows pointing at it and pointing out from it with similar cylindrical radius? Or at least I want to know the sign of the net current at a certain place to determine the direction of current.

Offline Anders Blom

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Re: About the unit of external potential
« Reply #8 on: December 26, 2012, 15:42 »
If you consider the definition of the unit "electronvolt", the conversion factor is obvious ;)

All quantities which are expressed on a 3D grid Q(x,y,z) support arithmetic operations. Transmission pathways is thus not included immediately, since it's a discrete function of the pairs of all atoms. But, since ATK uses Python, you can always extract the numbers and perform any operations you want.

The proper quantity to compute for the position-dependence of the current is the current density, although the pathways can in a sense be used to approximate it.

Offline BlackBarrel

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Re: About the unit of external potential
« Reply #9 on: December 27, 2012, 11:45 »
If you consider the definition of the unit "electronvolt", the conversion factor is obvious ;)

All quantities which are expressed on a 3D grid Q(x,y,z) support arithmetic operations. Transmission pathways is thus not included immediately, since it's a discrete function of the pairs of all atoms. But, since ATK uses Python, you can always extract the numbers and perform any operations you want.

The proper quantity to compute for the position-dependence of the current is the current density, although the pathways can in a sense be used to approximate it.

Thank you, Dr Anders Blom. Well then potential in in unit of eV has its value unchanged if in unit of V, right? What I feel strange is when I calculate the external potential of a device with a gate, the potential at the metallic region (which is about 18eV) doesn't equal what I set in the script (10V) if Neumann boundary condition is employed. There is no such problem with Dirichlet boundary condition. I'm using ATK 12.2. Is it a bug?

Also, the electric field derivated from the external potential is a little parabolic inside the dielectric region. Shouldn't it be linear?

Offline Anders Blom

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Re: About the unit of external potential
« Reply #10 on: December 27, 2012, 11:53 »
Basically yes, the difference between potential and potential energy is just "e" as in "e"V vs. V. There may be a sign difference though!

There is a bug in the multigrid method for Neumann in 12.2, I'm not sure it would affect the case you mention, it usually manifests itself as a failure of convergence (lots of warning messages in the log file) rather than anything else.

The field is computed fully self-consistently, so there is no inherent reason for it to be linear or any other shape.